AMC 8 Exam Session 2022-2023

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AMC8/MathCount Practice Session 2022-2023

The AMC 8 is a 25-question, 40-minute, multiple choice examination in middle school mathematics designed to promote the development of problem-solving skills.

Jun 23 2023 to Sep 01 2023

Tuesday, Dec. 23, 2023
10:30 AM EDT - 12:00 PM EDT

Sharad Goyal

9 Spots Open

Enroll

American Mathematics Competition 8 (replaced AJHSME) or AMC 8 (Grade 7 and Grade 8) is the first step toward International Math Olympiad in the United States (USAMO). Outstanding students participate in this festival of mathematics every year to test their mettle. We provide an opportunity for students to develop positive attitudes towards analytical thinking and mathematics that can assist in future careers. If you will join us you won't go to regret it at any time. We have the best educators, a Tremendous helping team, excellent online support, hassle-free learning. Level 1(contain 10 Q),Level 2(contain 15 Q),Level 3(contain 20 Q),Level 4(contain 25 Q) 
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Jan 18 2023 to Jan 24 2023 
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Here are a few examples of course problems with their solutions.

Question On February 13 The Oshkosh Northwester listed the length of daylight as 10 hours and 24 minutes, the sunrise was 6:57AM, and the sunset as 8:15PM, The length of daylight and sunrise were correct, but the sunset was wrong. When did the sun really set? 
(A) 5:10 pm (B) 5:21 pm (C) 5:41 pm (D) 5:57 pm (E) 6:03 pm 
Answer The problem wants us to find the time of sunset and gives us the length of daylight and time of sunrise. So all we have to do is add the length of daylight to the time of sunrise to obtain the answer. Convert 10 hours and 24 minutes into 10:2410:24 in order to add easier.

Problem Isabella must take four 100-point tests in her math class. Her goal is to achieve an average grade of 95 on the tests. Her first two test scores were 97 and 91. After seeing her score on the third test, she realized she can still reach her goal. What is the lowest possible score she could have made on the third test? 
(A) 90 (B) 92 (C) 95 (D) 96 (E) 97 
Solution Isabella wants an average grade of 9595 on her 4 tests; this also means that she wants the sum of her test scores to be at least 95 \times 4 = 38095×4=380 (if she goes over this number, she'll be over her goal!). She's already taken two tests, which sum to 97+91 = 18897+91=188, which means she needs 192192 more points to achieve her desired average. In order to minimize the score on the third test, we assume that Isabella will receive all 100100 points on the fourth test. Therefore, the lowest Isabella could have scored on the third test would be 192-100 = \boxed{\textbf{(B)}\ 92}192−100= 92.

AMC 8 Exam Session 2022-2023

American Mathematics Competition 8 (replaced AJHSME) or AMC 8 is the first step toward International Math Olympiad in the United States (USAMO). Outstanding students participate in this festival of mathematics every year to test their mettle. This contest aims to provide an opportunity for the students so that they can have a positive attitude towards the challenging problems in Mathematics.

Jan 18 2023 to Jan 24 2023

Tuesday
10:30 AM EDT - 07:00 PM EDT
Jan 18, 2023 to Jan 24, 2023

Sharad Goyal

9 Spots Open

Enroll

Here are a few examples of course problems with their solutions.