AMC 8
American Mathematics Competition 8 (replaced AJHSME) or AMC 8 (Grade 7 and Grade 8) is the first step toward International Math Olympiad in the United States (USAMO). Outstanding students participate in this festival of mathematics every year to test their mettle. We provide an opportunity for students to develop positive attitudes towards analytical thinking and mathematics that can assist in future careers. If you will join us you won't go to regret it at any time. We have the best educators, a Tremendous helping team, excellent online support, hassle-free learning. Level 1(contain 10 Q),Level 2(contain 15 Q),Level 3(contain 20 Q),Level 4(contain 25 Q)
Jan 18 2024 to Jan 24 2024
Here are a few examples of course problems with their solutions.
Question On February 13 The Oshkosh Northwester listed the length of daylight as 10 hours and 24 minutes, the sunrise was 6:57AM, and the sunset as 8:15PM, The length of daylight and sunrise were correct, but the sunset was wrong. When did the sun really set?
(A) 5:10 pm (B) 5:21 pm (C) 5:41 pm (D) 5:57 pm (E) 6:03 pm
Answer The problem wants us to find the time of sunset and gives us the length of daylight and time of sunrise. So all we have to do is add the length of daylight to the time of sunrise to obtain the answer. Convert 10 hours and 24 minutes into 10:2410:24 in order to add easier.
Problem Isabella must take four 100-point tests in her math class. Her goal is to achieve an average grade of 95 on the tests. Her first two test scores were 97 and 91. After seeing her score on the third test, she realized she can still reach her goal. What is the lowest possible score she could have made on the third test?
(A) 90 (B) 92 (C) 95 (D) 96 (E) 97
Solution Isabella wants an average grade of 9595 on her 4 tests; this also means that she wants the sum of her test scores to be at least 95 \times 4 = 38095×4=380 (if she goes over this number, she'll be over her goal!). She's already taken two tests, which sum to 97+91 = 18897+91=188, which means she needs 192192 more points to achieve her desired average. In order to minimize the score on the third test, we assume that Isabella will receive all 100100 points on the fourth test. Therefore, the lowest Isabella could have scored on the third test would be 192-100 = \boxed{\textbf{(B)}\ 92}192−100= 92.
Register for AMC 8 Talent Academy official AOPS invitation ((Official Talent Academy registration)
Talent Academy Official AMC 8 Jan 18 10 AM (Official Skype Channel to conduct exam)
Talent Academy Parents/Student Registration (Not required for Talent Academy students)
Important Notes
If your school is sponsoring then you are not eligible to register with us.
Students must take half time off from school to take the official AMC 8 exams
Summer enrollments are live. Assistant teachers will be available exclusively for summer batches who will be available to assistant students anytime between 9 AM- 1 PM EST.